Newton's root finding method

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Revision as of 14:20, 3 February 2010 by A WASSERMANN (talk | contribs)

xo is the start value. Drag it.

You may change the function term here:
f(x) =
 

You also may try the following function terms:

  • [math]\displaystyle{ Math.sin(x) }[/math]
  • [math]\displaystyle{ Math.exp(x) }[/math]
  • [math]\displaystyle{ Math.pow(2,x) }[/math]
  • [math]\displaystyle{ 1-2/(x*x) }[/math]

The underlying JavaScript code