# Difference between revisions of "Inequalities"

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ineq = b.create('inequality', [line]), | ineq = b.create('inequality', [line]), | ||

</source> | </source> | ||

− | and an | + | and an inequality of this line have to be created. |

+ | |||

+ | In case ''a = 0'', that is if the equation of the line is ''bx + c = 0'', the area of the inequality | ||

+ | ''bx + c <= 0'' is shown. | ||

+ | |||

If one wants to show "greater than", ''inverse:true'' has to be used: | If one wants to show "greater than", ''inverse:true'' has to be used: | ||

<source lang="javascript"> | <source lang="javascript"> | ||

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The first, black line has the equation ''y = c'' or ''0 = -1y + 0x + c'', | The first, black line has the equation ''y = c'' or ''0 = -1y + 0x + c'', | ||

the second, blue line has the equation ''y = 2/3 x + 1'' or ''0 = -3y + 2x +1''. | the second, blue line has the equation ''y = 2/3 x + 1'' or ''0 = -3y + 2x +1''. | ||

− | |||

− | |||

− | |||

<jsxgraph width="400" height="400" box="box1"> | <jsxgraph width="400" height="400" box="box1"> |

## Revision as of 15:12, 2 June 2017

To graph inequalities of the form
*y <= b/a * x + c/a*
a line of the form

```
line = b.create('line', [c, b, a]);
ineq = b.create('inequality', [line]),
```

and an inequality of this line have to be created.

In case *a = 0*, that is if the equation of the line is *bx + c = 0*, the area of the inequality
*bx + c <= 0* is shown.

If one wants to show "greater than", *inverse:true* has to be used:

```
line = b.create('line', [c, b, a]);
ineq = b.create('inequality', [line], {inverse:true}),
```

In the following example, two lines are shown.
The first, black line has the equation *y = c* or *0 = -1y + 0x + c*,
the second, blue line has the equation *y = 2/3 x + 1* or *0 = -3y + 2x +1*.

### The JavaScript code

```
var b = JXG.JSXGraph.initBoard('box1', {boundingbox: [-5, 5, 5, -5], axis:true});
var c = b.create('slider', [[-3,4], [2,4], [-5,1,5]]),
line1 = b.create('line', [function() { return [c.Value(), 0, -1]; }], {strokeColor: 'black'}),
ineq1 = b.create('inequality', [line1], {inverse: true}),
line2 = b.create('line', [1, 2, -3]), // Line y = 2/3 x + 1 or 0 = -3y + 2x +1
ineq2 = b.create('inequality', [line2], {fillColor: 'yellow'});
```