Rose
From JSXGraph Wiki
A rose or rhodonea curve is a sinusoid plotted in polar coordinates. Up to similarity, these curves can all be expressed by a polar equation of the form
- [math]\displaystyle{ \!\,r=\cos(k\theta). }[/math]
If k is an integer, the curve will be rose shaped with
- 2k petals if k is even, and
- k petals if k is odd.
When k is even, the entire graph of the rose will be traced out exactly once when the value of θ changes from 0 to 2π. When k is odd, this will happen on the interval between 0 and π. (More generally, this will happen on any interval of length [math]\displaystyle{ 2\pi }[/math] for [math]\displaystyle{ k }[/math] even, and [math]\displaystyle{ \pi }[/math] for [math]\displaystyle{ k }[/math] odd.)
The quadrifolium is a type of rose curve with n=2. It has polar equation:
- [math]\displaystyle{ r = \cos(2\theta), \, }[/math]
with corresponding algebraic equation
- [math]\displaystyle{ (x^2+y^2)^3 = (x^2-y^2)^2. \, }[/math]
The JavaScript code to produce this picture
<jsxgraph width="500" height="500" box="box2">
var b2 = JXG.JSXGraph.initBoard('box2', {axis:true,originX: 250, originY: 250, unitX: 25, unitY: 25});
var f = b2.createElement('slider', [[1,8],[5,8],[0,4,8]]);
var len = b2.createElement('slider', [[1,7],[5,7],[0,2,2]]);
var k = b2.createElement('slider', [[1,6],[5,6],[0,2,10]]);
var c = b2.createElement('curve', [function(phi){return f.Value()*Math.cos(Math.floor(k.Value())*phi); }, [0, 0],0, function(){return len.Value()*Math.PI;}],
{curveType:'polar', strokewidth:2});
</jsxgraph>
