Inequalities: Difference between revisions

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In the following example, two lines are shown.
The first, black line has the equation ''y = c'' or ''0 = -1y + 0x + c'',
the second, blue line has the equation ''y = 2/3 x + 1'' or ''0 = -3y + 2x +1''


<jsxgraph width="400" height="400" box="box1">
<jsxgraph width="400" height="400" box="box1">

Revision as of 13:06, 16 December 2014

To graph inequalities of the form ay + bx + c <= 0 a line of the form

line = b.create('line', [c, b, a]);
ineq = b.create('inequality', [line]),

and an equality of this line have to be created. If one wants to show "greater than", inverse:true has to be used:

line = b.create('line', [c, b, a]);
ineq = b.create('inequality', [line], {inverse:true}),

In the following example, two lines are shown. The first, black line has the equation y = c or 0 = -1y + 0x + c, the second, blue line has the equation y = 2/3 x + 1 or 0 = -3y + 2x +1

The JavaScript code

var b = JXG.JSXGraph.initBoard('box1', {boundingbox: [-5, 5, 5, -5], axis:true});
var c = b.create('slider', [[-3,4], [2,4], [-5,1,5]]),
    line1 = b.create('line', [function() { return [c.Value(), 0, -1]; }], {strokeColor: 'black'}),
    ineq1 = b.create('inequality', [line1], {inverse: true}),

    line2 = b.create('line', [1, 2, -3]), // Line y = 2/3 x + 1 or 0 = -3y + 2x +1
    ineq2 = b.create('inequality', [line2], {fillColor: 'yellow'});