Extended mean value theorem: Difference between revisions
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The ''extended mean value theorem'' (also called ''Cauchy's mean value theorem'') is: | The ''extended mean value theorem'' (also called ''Cauchy's mean value theorem'') is: | ||
Let | |||
:<math> f, g: [a,b] \to \mathbb{R}</math> | :<math> f, g: [a,b] \to \mathbb{R}</math> | ||
that are differentiable on the open interval < | be continuous functions that are differentiable on the open interval <math>(a,b)</math>. | ||
If <math>g'(x)\neq 0</math> for all <math>x\in(a,b)</math>, | |||
then there exists a value <math>\xi \in (a,b)</math> such that | |||
:<math> | |||
\frac{f'(\xi)}{g'(\xi)} = \frac{f(b)-f(a)}{g(b)-g(b)}. | |||
</math> | |||
<jsxgraph width="600" height="400" box="box"> | <jsxgraph width="600" height="400" box="box"> |
Revision as of 16:24, 29 January 2019
The extended mean value theorem (also called Cauchy's mean value theorem) is: Let
- [math]\displaystyle{ f, g: [a,b] \to \mathbb{R} }[/math]
be continuous functions that are differentiable on the open interval [math]\displaystyle{ (a,b) }[/math]. If [math]\displaystyle{ g'(x)\neq 0 }[/math] for all [math]\displaystyle{ x\in(a,b) }[/math], then there exists a value [math]\displaystyle{ \xi \in (a,b) }[/math] such that
- [math]\displaystyle{ \frac{f'(\xi)}{g'(\xi)} = \frac{f(b)-f(a)}{g(b)-g(b)}. }[/math]
The underlying JavaScript code
var board = JXG.JSXGraph.initBoard('box', {boundingbox: [-5, 10, 7, -6], axis:true});
var p = [];
p[0] = board.create('point', [0, -2], {size:2});
p[1] = board.create('point', [-1.5, 5], {size:2});
p[2] = board.create('point', [1, 4], {size:2});
p[3] = board.create('point', [3, 3], {size:2});
// Curve
var fg = JXG.Math.Numerics.Neville(p);
var graph = board.create('curve', fg, {strokeWidth:3, strokeOpacity:0.5});
// Secant
line = board.create('line', [p[0], p[3]], {strokeColor:'#ff0000', dash:1});
var df = JXG.Math.Numerics.D(fg[0]);
var dg = JXG.Math.Numerics.D(fg[1]);
// Usually, the extended mean value theorem is formulated as
// df(t) / dg(t) == (p[3].X() - p[0].X()) / (p[3].Y() - p[0].Y())
// We can avoid division by zero with that formulation:
var quot = function(t) {
return df(t) * (p[3].Y() - p[0].Y()) - dg(t) * (p[3].X() - p[0].X());
};
var r = board.create('glider', [
function() { return fg[0](JXG.Math.Numerics.root(quot, (fg[3]() + fg[2]) * 0.5)); },
function() { return fg[1](JXG.Math.Numerics.root(quot, (fg[3]() + fg[2]) * 0.5)); },
graph], {name: '', size: 4, fixed:true, color: 'blue'});
board.create('tangent', [r], {strokeColor:'#ff0000'});