Logistic process

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Logistic population growth model

In time [math]\displaystyle{ \Delta t }[/math] the population grows by [math]\displaystyle{ \alpha\cdot y -\tau\cdot y^2 }[/math] elements: [math]\displaystyle{ \Delta y = (\alpha\cdot y- \tau\cdot y^2)\cdot \Delta t }[/math], that is [math]\displaystyle{ \frac{\Delta y}{\Delta t} = \alpha\cdot y -\tau\cdot y^2 }[/math].

With [math]\displaystyle{ \Delta t\to 0 }[/math] we get [math]\displaystyle{ \frac{d y}{d t} = \alpha\cdot y -\tau\cdot y^2 }[/math], i.e. [math]\displaystyle{ y' = \alpha\cdot y -\tau\cdot y^2 }[/math].

The initial population is [math]\displaystyle{ y(0)= s }[/math], [math]\displaystyle{ \tau:=0.3 }[/math].

Other models

The JavaScript code

var brd = JXG.JSXGraph.initBoard('box1', {boundingbox: [-0.5, 11.5, 14.5, -11.5], axis:true});
var t = brd.create('turtle',[4,3,70]);
var s = brd.create('slider', [[0,-5], [10,-5],[0,0.5,5]], {name:'s'});
var alpha = brd.create('slider', [[0,-6], [10,-6],[-1,0.9,2]], {name:'α'});

t.hideTurtle();
            
var A = 5;
var tau = 0.3;
            
function clearturtle() {
  t.cs();
  t.ht();
}
            
function run() {
  t.setPos(0,s.Value());
  t.setPenSize(4);
  dx = 0.1; // global
  x = 0.0;  // global
  loop();
}
             
function loop() {
  var dy = (alpha.Value()*t.Y()-tau*t.Y()*t.Y())*dx; // Logistic process
  t.moveTo([dx+t.X(),dy+t.Y()]);
  x += dx;
  if (x<20.0) {
     setTimeout(loop,10);
  }
}